1.0 mol /1.0 mol KClO3 + NH4NO3 --> KNO3 + NH4ClO3 ... add water to make solution satured , wait reaction for 1 hr , add 90 ml ethanol , the
KNO3 will precipatate , filter the solution , take to freezer at -18°C for 3 hrs , filter again the the bit of KNO3 (note!) a bit of NH4ClO3 will
preciptate , but no problem ,Now the solution after filtering , is taken to dry at 40°C ,and this is NH4ClO3 ..... has low point melt around of
100°C e decomposes quickly without residue solid.
Is possible describe preparation in grams ? For example : In 100g H2O added 10g KClO3 + 10g NH4NO3. Wait 1 hour. (temperature during 1 hour ?)
Dissolved all (estimate) Why waiting 1 hour ? OK, next: Added 90g ethanol. In this time, KNO3 will precipitate out. Filtered, and use solution.
Solution content 90% NH4ClO3 + 10% KNO3. Go to solution on - 18 C. Again filtered and precipitate out is again KNO3. Solution content NH4ClO3 99% + 1%
KNO3 OK. heated on 40C , respectively evaporate H2O + ethanol. Dry crystals NH4ClO3 arises ? You can added values in grams? Thanks.
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