Edit: Actually, are you sure its V2O5 formed on the support after calcination? I recall oxalic acid can reduce some metal species, particularly those
in the higher oxidation states. I suspect the vanadium is not +5 in the solution, given the blue colouration, but whether it returns on activation at
temperature or not I don't know?
[Edited on 6-2-2017 by DJF90] |