Quote: Originally posted by symboom | I think I figured out the smell and the goo its paraformaldehyde
So methanol oxidizes to aldehyde in oxone solution? |
In my opinion the unspecified agent is an activitating transition metal impurity (likely Fe(ll) here) working with the 2KHSO5·KHSO4·K2SO4. For
associated properties, see http://www.cruso.es/FICHAS/33Oxone.htm.
Of special concern working with KHSO5 is the presence of transition metal impurities (like cobalt, for example, but no reference citing this is indeed
a contaminant here), as one can be deceived as to what is actually occurring! In fact, a trace of cobalt ions in the presence of HSO5- can produce the
powerful sulfate radical anion (see "COBALT/PEROXYMONOSULFATE AND RELATED OXIDIZING REAGENTS FOR WATER TREATMENT" a thesis by Georgios P. Anipsitakis,
https://etd.ohiolink.edu/rws_etd/document/get/ucin1130533674... ). To quote from the dissertation:
" It was found that when Co(II), Ru(III) and Fe(II) interact with KHSO5, freely diffusible sulfate radicals are the primary species formed."
Note, the sulfate radical, .SO4, is just a little less potent than the hydroxyl radical, .OH, which will breakdown compounds with a sequence of
abstraction reactions. Also, in the presence of O2 (or a contributing agent like KHSO5), an oxygen addition reaction could occur with the breakdown
products.
One could also describe the sole action of Fe(ll) on KHSO5 (which acts here as a H2O2 substitute) as a so called fenton-type reaction producing
powerful sulfate (as opposed to hydroxyl) radicals.
[Edited on 11-6-2017 by AJKOER] |