Quote: | Al + Na2CO3 + H2O => Nothing happens. You just get a solution of Na2CO3 with pieces of aluminium in it...At least this is what I got when I tried
it 2 minutes ago.
|
If the aluminum oxide layer is removed (mercury amalgam could be used), the aluminum will reduce the H2O, leaving Na2CO3 in solution and Al(OH)3 in
suspension. It should react slowly, since Na2CO3 is basic and will dissolve a small amount of aluminum (not much, since CO3-- is stronger than AlO2-,
correct?).
At high temperatures, the aluminum will reduce carbonate to carbide, releasing sodium as vapor at this temperature. This would be written: 3Na2CO3(l)
+ 10Al(l) = Al4C3(s) + 3Al2O3(l) + 6Na(g).
( (l) is liquid, (s) solid, (g) gas. Na2CO3 and/or Al may be gas at the required temperature, and I'm not sure if Al4C3 will decompose to Al(g) +
C(s).)
This reaction is probably not self-sustaining. However, the analogous reaction using sulfate or nitrate instead of carbonate, proceeds quickly.
Tim |