Is this true? As far as I know, Ca(OH)2 is moderately soluble in water, while CaSO4 is insoluble. So, I can imagine that you can make a (dilute)
solution of KOH by mixing stoichiometric amounts of solutions of K2SO4 and Ca(OH)2. Both K2SO4 and Ca(OH)2, however, are only moderately soluble, so
your solution will be dilute. It still will contain a little Ca(2+) and SO4(2-) ions as well and it will be hard to add solutions in exact
stoichiometric amounts. |