Filemon - 30-9-2006 at 14:49
What does it take place reaction? Al + NH4Cl => AlCl3 + NH3 + H2?
12AX7 - 30-9-2006 at 20:10
Yeah, that seems reasonable. Note that NH4Cl <--> NH3 + HCl (decomposition, not sublimation). This also fights with AlCl3 sublimation, and
(though probably at higher temperatures) NH3 + Al = AlN + 3H (1.5 H2).
So hmm, you get NH4Cl --> NH3 + HCl at high temperature. Mixed with aluminum (filings, turnings, powder?) the reaction Al + 3HCl --> AlCl3 +
1.5 H2 takes place; AFAIK, H2 is never a strong enough reducing agent vs. aluminum, so this reaction is strongly to the right. Therefore, the
reaction 3NH4Cl + Al = 3NH3 + AlCl3 + 1.5 H2 must proceed.
This sounds like a suspiciously good way to make AlCl3, what's wrong with it?
Tim
not_important - 30-9-2006 at 22:50
It works, but A) it is difficult to separate unreacted NH4Cl from AlCl3, and B) AlCl3 and NH3 form a complex
1st page on complex
http://pubs.acs.org/cgi-bin/abstract.cgi/inocaj/1975/14/i06/...