If I have a 3785ml bottle of %8.25 NaClO, and I use: 3NaClO + C<sub>3</sub>H<sub>6</sub>O --> CHCl<sub>3</sub>
+ 2NaOH + NaOCOCH<sub>3</sub> to produce chloroform, how do I know how much bleach/acetone I need?Metacelsus - 24-4-2015 at 18:59
The stoichiometry implies 32 milliliters of acetone per liter of 8.25% bleach.
Basically, just use molar masses and densities to compute how much you need.Amos - 24-4-2015 at 19:00
You have the equation, the chemical formulas, the amount of one reactant, and access to a periodic table online.
What's stopping you from calculating it yourself?RaD - 24-4-2015 at 19:05
Basically, just use molar masses and densities to compute how much you need.
How??Zyklon-A - 24-4-2015 at 19:29
First find the molar mass of each compound in the reaction. Next find the molar ratio of each compound (3/1 hypochorite ion/acetone in this case).
This tells you how many grams of each compound is needed. Since the sodium hypochlorite is only a 8.25% solution, multiply x (three times the MM of
sodium hypochlorite) by 8.25 to find how much bleach (in grams) you need to react with one mole of acetone.
At this point you could find the density of a 8.25% sodium hypochlorite sol.
