Sciencemadness Discussion Board

Does this series converge?

Eddygp - 4-4-2015 at 01:34

Another math challenge:
How would you tell whether this series converges or does not converge (computing the sum of 10000000000 values is not allowed as a demonstration)?



[Edited on 4-4-2015 by Eddygp]

[Edited on 4-4-2015 by Eddygp]

j_sum1 - 4-4-2015 at 02:52

well you could substitute (pi/2 - pi/2n) into the infinite series for cos.
Then you have some fun expanding and simplifying and pulling out series you know do converge. If that turns out to be the whole series then you have your answer.

Another approach would be to apply an identity
cos(A-B) = cosAcosB + sinAsinB
then see if something interesting emerges.

I am too lazy to do either now. My guess is that it will converge since it can be shown easily that successive terms get smaller. However, (pi/2 - pi/2n) converges to pi/2 in a manner similar to a harmonic series which just marginally diverges and cos has a point of inflection (so approaches linear) so it could easily go the other way.

Have fun.

j_sum1 - 4-4-2015 at 03:58

Forget nesrly evrrything I said above. Neither approsch will get you far.

There is a simple and elegant proof but I am not goint to yry typing it on my phone. (That's what Fermat would have said isn't it?)

It does not converge.

Etaoin Shrdlu - 4-4-2015 at 09:04

Damnit j_sum. None of mine are elegant. Come back and tell me what yours is.

Limit comparison to the harmonic series:

cos(pi/2-pi/(2n))=sin(pi/(2n)

sin(pi/(2n) is positive for n>=1
1/n is positive for n>=1

lim sin(pi/(2n))/(1/n) n->inf = pi/2

Harmonic series is divergent, so cos(pi/2-pi/(2n)) is divergent.

woelen - 4-4-2015 at 12:15

I indeed would go along the lines of Etaoin Shrdlu. For n going to infinity, the funtion can be approximated as pi/2n and the series for that is divergent.

gdflp - 4-4-2015 at 12:39

I agree with Etaoin Shrdlu. I could explain it in layman's terms, but I'm not sure how to formally write it.
Quote:
computing the sum of 10000000000 values is not allowed as a demonstration
And Eddygp, I don't suppose that has anything to do with my response to your last math problem.:P

aga - 4-4-2015 at 14:07

Quote: Originally posted by gdflp  
I could explain it in layman's terms, but I'm not sure how to formally write it.

No it doesn't.

Simples !