It's quite well know that sulfuric acid will protonate chloride without much oxidation (if any). This is how myself and many people here produce anhydrous HCl gas.
The reaction is:
NaCl + H2SO4 → HCl + NaHSO4
Also twice the molar concentration of NaCl can be used and with strong heating the sodium bisulfate can also protonate the remaining NaCl.
But when it comes to bromide, some of the bromide gets oxidized to bromine. Of course if bromide is getting oxidized, something is getting reduced,
the only possibility I can think of is the sulfur in sulfate. My guess is this reaction is occurring:NaBr +
H2SO4 → .5 Br2 + NaSO3 + H2O.
Is this correct?
Of course this is a equilibrium reaction, which also produces HBr according to an analogous reaction to the one shown with NaCl at the top. Does
anyone where the equilibrium lies and to what extent both reactions take place?
I want to minimize the reaction producing bromine as bromine can easily be produced via oxidation with hydrogen peroxide or similar.
The goal is to find a easy way to make HBr gas from NaBr and sulfuric acid, just like HCl.
Here's another good read, but it still gives no information about the degree of the equilibrium: http://www.chemguide.co.uk/inorganic/group7/halideions.html
[Edited on 16-1-2015 by Molecular Manipulations]