Wanting "to do something" with Cadmium, I stumbled onto this excellent thread, so if no one minds I'll revive it.
Firstly I want to comment on Magpie's excellent method of separating Cd2+ and Ni2+, by means of sulfide solubility difference, by putting a bit of
math beef on these bones.
The solubility constants for CdS and NiS respectively are 8.0 x E-27 and 3.0 x E-19.
The acid dissociation constants for H2S are:
[H3O+]x[HS-]/[H2S] = 1 x E-7 (K1)
and [H3O+]x[S2-]/[HS-] = 6.4 x E-16 (K2)
From this page http://www.telusplanet.net/public/jcarroll/ION.HTM can be gleaned that the solubility of H2S in water is about 0.1 M, remarkably independent of pH
(apart of course for very high pHs).
Magpie adjusted the solution to 0.3 M HCl, thus [H3O+] ≈ 0.3 M.
Since as the dissociation of H2S in acid conditions is completely negligible, both [H2S] ≈ 0.1 M and [H3O+] ≈ 0.3 M are very good
approximations.
Now isolate [HS-] from K1 and insert it in into K2, then isolate for [S2-]:
[S2-] ≈ K1 x K2 x ([H2S] / [H3O+]^2)
or in Magpie's conditions, [S2-] ≈ K1 x K2 = 6 x E-23 (pretty low, huh!)
Assume for argument's sake that prior to saturation with H2S, [Cd2+] ≈ [Ni2+] ≈ 0.1 M, then it's clear that [Cd2+]x[S2-] far exceeds the
solubility constant of 8.0 x E-27 (by a factor of about 10,000) but that [Ni2+]x[S2-] is much lower than the solubility constant of 3.0 E-19 (by about
the same factor of 10,000). The separation of Cd and Ni by this method must thus be very near complete.
I'm guessing (w/o peeking) that Cu2+ would precipitate with Cd2+ but not for instance ZnS.
I'm hoping in the next few weeks to make some high purity Cadmium metal by electrolysis of molten anhydrous CdCl2. I haven't decided to start from
spent batteries or from commercial CdS yet...
[Edited on 29-7-2009 by blogfast25] |