Dancer - 30-5-2005 at 06:54
In an experiment I am trying to conduct one of the instructions are as follows:
“a hot vapor was fed into the solution for 45 minutes, and a crystal was precipitated”
The solution is an organic compound in water. I fed steam into the mixture as the hot vapour but nothing happened. Am I wrong in my assumption that
steam can be regarded as “hot vapour”?
chemoleo - 30-5-2005 at 07:03
Eh?
If you clarify a little as to exactly what you did/used, it might help!
neutrino - 30-5-2005 at 12:05
That doesn’t sound like ordinary water vapor there. Could it be some sort of reagent?
Dancer - 31-5-2005 at 11:08
I am trying to replicate an patent I got on the web making creatine. It is a reaction of N-methylglycine with S-methylisothiourea sulfate in water .
The creatine is then supposed to crystallize out. According to the patent if you feed a hot vapour in the solution you get higher yields.
I think because it is a patent they are deliberately a bit vague on what the hot vapour is.
BromicAcid - 1-6-2005 at 10:09
Maybe it's the 'vapor' part that's throwing the reaction off, maybe it just wants a hot gas, to remove some of the solvent.
Bubbling air through H2O2 increases the concentration by removing the more volitile water, maybe this hot gas increases the concentration of your
desired product and thereby causes more to precipitate.
Maybe it helps to form nucleation centers for the solid or maybe it is something rich in CO2 to increase the acidity of the solution resulting in
precipitation, or maybe it removes some other volatile product present thereby decreasing the solubility of your product (maybe removing ammonia or
something else there). This hot gas/vapor could serve any of a number of purposes.
Madandcrazy - 20-6-2005 at 06:45
BromicAcid,
maybe the ammonium sulfate as a inhibitor by the fine precipitation.