Hermes_Trismegistus - 21-2-2005 at 08:20
Sorry if this is a silly question but my textbooks are theory heavy and practical light.
How are the r and s enantiomers of a racemic mixture customarily seperated from each other?
sparkgap - 21-2-2005 at 09:04
If the chiral compound in question is a base, it is reacted with (optically pure, of course) a chiral acid, and vice versa.
The diastereomers thus produced behave differently enough that HPLC can be used to separate them.
hope this helps.
sparky(^_^)
Kanem - 21-2-2005 at 09:45
When they were first discovered, enantiomeres were separated by evaporating the solvent and separating the remaining crystals, which consisted of
only one enantiomer, by hand under the microscope.
Kanem
sparkgap - 22-2-2005 at 06:29
Pasteur-style enantiomer separation would not be a practical method of resolving a racemic mixture, though. 
This site may be of interest to everybody interested in resolution.
sparky (^_^)
JohnWW - 22-2-2005 at 09:16
One possibility could be separation by means of ion-exchange, by passing the mixture (if it has ionizable carboxylic acid or ammonium salt groups)
through an ion-exchange material consisting of a polymer containing chiral carbon (or other e.g. nitrogen) atoms. This is just an idea; I am uncertain
whether anyone has thought of or tried it.
unionised - 22-2-2005 at 11:36
Broadly the same idea has been tried.
http://www.ncbi.nlm.nih.gov/entrez/query.fcgi?cmd=Retrieve&a...
You can also use a nonchiral stationary phase and a chiral solvent, but that's rather expensive.
I seem to remember that you can produce chiral products by photochemical reactions using circularly polarised light. (lousy yield, but therotically
elegant.)
Pastuer's method is a pain in the neck, but it's the only way that I can think of that doesn't start with something chiral.
[Edited on 22-2-2005 by unionised]