CHRIS25 - 23-3-2013 at 09:33
When you titrate copper chloride (CuCL2) with Sodium Hydroxide to find the amount of free H+ ions not tied up with copper ions the procedure is a 2:1
ratio in the actual titration calculations because:
CuCl2 + 2NaOH => Cu(OH)2 + 2NaCl
Yet the copper chloride is rich in the HCl, where normally a titration with NaOH would require a 1:1 ratio in titration calculations.
I have in my notes from this site records of where the 1:1 ratio was used and I do not understand why, since you are seeking a neutralisation between
the copper chloride with sodium hydroxide to establish molarity of copper chloride that is free H+ ions in solution.