123chem - 29-6-2004 at 10:29
anyone know how to figure this out:
N2 + 3 H2 = 2 NH3
if 1200 g of N2 is reacted with excess hydrogen, what is the theoretical yeild of NH3
chemoleo - 29-6-2004 at 10:49
Now, there is a Beginnings section to ask questions like that.
A simple solution would be (but surely not appreciated by any examiner):
1200g x 17/14 = 1457.1 g of NH3...
Don't ask what I am doing, thats for you to figure 
Proteios - 29-6-2004 at 11:05
lol.....ive got a better answer than that.....
the theoretical yield is 100 % 
The_Davster - 29-6-2004 at 11:15
theres also this way.
1200g/28.02 x 2 x 17.04
=1459.5g of NH3
Which is about the same as Chemoleo's way, but mine is more accurate
sanity gone - 29-6-2004 at 11:17
Lets do the math:
Edit:
Someone else beat me to writing it out, so I drew it out for you.
[Edited on 6/29/2004 by sanity gone]
[Edited on 6/29/2004 by sanity gone]
The_Davster - 29-6-2004 at 11:20
sanity gone: It was suposed to be 2 mol NH3 over 1 mol N2.
sanity gone - 29-6-2004 at 11:21
haha, I saw that right after I posted it, damn ADD.