As to the specific technical argument, you're saying that the reactor liquid would boil away, extinguishing any chance at criticality, which I would
agree with if we were certain that this is what would happen, but which we are not certain of. In a pure evaporation scenario, you've
made the argument (implicitly) that the solute will dissipate with evaporating solvent. This may not always be true. The boiling point of FLiBe is
1430 °C. The boiling point of ThF4 is 1680 °C. If the FLiBe eutectic boils off separately from the ThF4 (which I
don't know one way or the other), then there's a temperature range where solvent evaporation leads to fuel concentration. Therefore, until we have
experimental data on what happens when the liquid fuel-solvent mixture boils, it's improper to argue on grounds of plausibility that there's no risk
here.But there's another way in which it seems you've misconstrued my original argument. The argument I made in my first post is that there's a
plausible scenario where the solvent FLiBe does not evaporate away, but rather reacts away, leaving the solute, which contain all the fuel nuclides
alone, with neither moderator nor coolant. This can happen simply at the liquid operating temperature, which is a few hundred degrees below its
boiling point. The temperature rise from criticality of concentrated solute would happen, in this scenario, after the solvent is already gone.
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