Am I just underthinking this but if the con of 37% HCl solution is 12 M
then 1000/12 (ie 1L/12M) = 83.333mL/mol of conc. HCl, made up to 1L.
Will give a 1N solution.
If it is 32%, that is roughly 10M. So 100mL/mol...
For a 2N solution double the amount of acid added to 3/4 of the desired
volume of water, then add the remainder of water to make your desired volume.
If you want to be absolutely accurate titrate it.
Scale appropriately for the amounts you want.
Good luck. |