Quote: Originally posted by Nitrosio  |
| Quote: Originally posted by dave321 | |
can you please explain the calculation. my A level chemistry is somewhat rusty after 46 years |
| Quote: Originally posted by Elemental Phosphorus | |||
Density of silver fulminate is 3.94 grams per ml (or g/cc) and density of silver azide is 4.98 grams per ml. Assuming the decomposition of silver proceeds as follows: 2AgN3 --> 2Ag + 3N2 And the decomposition of silver fulminate proceeds as follows: 2AgCNO --> 2Ag + 2CO + N2 Then the decomposition of one mole of silver azide or silver fulminate leads to the production of 1.5 moles of gaseous products. One mole of any ideal gas has the same volume at a specific temperature and pressure (so 1 mole of CO and one mole of N2 take up the same space in the same conditions) and that molar volume at 1atm of pressure and 0 degrees C is about 22.4 liters. 1 mole of silver azide or silver fulminate will then make approximate 33.6 liters of gas, assuming the gas is at 0C. Since 1 mole of silver azide weighs 149.88 grams, 1 gram of silver azide generates about 0.2242 liter of gas, or 224.2 cc. 1 mole of silver fulminate weighs approximately the same and henceforth 1 gram of the fulminate will also generate about 224.2 cc of gas. However, since the azide is denser, 1 cc of azide will generate about 1.116 liters of gas, while 1 cc of fulminate will generate about 0.883 liters of gas. This assumes the gas is generated at 0C, and obviously it will be hotter in an explosion, but it's a rough estimate. [Edited on 16-8-2021 by Elemental Phosphorus] |