Making an -accurate- replacement might not be easy to fabricate. Even if you figure out what the sensor IC is the construction of the probe must match
as well. You should weigh the cost of the probe against the time & tears to reverse-engineer it and the probability that it won't be accurate
because you couldn't match the physical layout and construction of the original.
The placement of the sensor is interesting. The cold-junction compensation for a thermocouple has to sense the temperature where the copper wire and
the thermocouple wire join. Putting the sensor in the probe handle allows the manufacturer to use copper wires from that point to the A/D in the base.
Cute. That also makes it impossible (as you've noticed) to just plug in a bare type K. You would have to put the IC against and at thermal equilibrium
to the copper-thermocouple wire join for your replacement probe to be consistent and accurate.
I'd agree with Metallophile. I'd vote for the IC sensor:
not a thermistor - resistance would vary far more than you've measured
not a diode - too high voltage drop and too little change with temperature
You've accounted for pins 1-2, 3-4. and 6. If 5 is connected to anything then it's a 3-pin IC.
You could put a 1K resistor in series with your meter set to a 10mA current range and measure the current between 6 and 1. If it's 5mA, then there
really ought to be a connection to pin 5 inside the unit for the output from a 3-pin IC which outputs a voltage dependent on temperature. If it's much
less, then it's a two-pin IC which draws current dependent on temperature. I believe that would be the commonest case.
By measuring the voltage at pin 5 (3-pin IC) or the current at pin 6 (2-pin IC) you can try to use that information to pick a suitable IC for your
probe. 1uA-1mV/C are common. It would require making a little test fixture with a 6-pin plug and socket. Bus 1, 2, 3, 4 and 5 across. Put your meter
& resistor in series with 6 on each side. You can also bus 6 across and measure voltage between 1 and 5. If you see 0V you definitely have a 2-pin
IC.
However.... all bets are off if the sensing IC output is digital. You'd need an oscilloscope to figure that one out. |