Do you really have Cu(ClO3)2? Could you make pictures of the original reagents, before you mix them?
I hardly believe that if you had Cu(ClO3)2 that it cleanly decomposes to CuCl2 and O2. I'm quite sure that on heating, this salt would decompose to
CuO or some basic chloride. If you have Cu(ClO3)2, then it will be a hydrated salt, Cu(ClO3)2.nH2O (I don't know the value of n, but it certainly is
not equal to 0). Such hydrated salts almost always decompose to the acid and the oxide on heating. In the case of chloric acid, there will be further
decomposition to Cl2, O2, HCl and water.
In general, mixing hygroscopic compounds can perfectly lead to formation of much less hygroscopic compounds. The mix may form a so-called double-salt.
Such a double-salt still has the same ions as the original salts, but arranged in a different crystal lattice (hence, it is not a coordination
complex). The other arrangement may make it much more difficult for water molecules to be trapped in/to adhere to the lattice and then you have a much
less hygroscopic compound. A nice example is so-called chlorine chalk. CaCl2 is very hygroscopic, it is a drying agent. Ca(ClO)2 also is hygroscopic.
It becomes wet on standing in humid air. But if you mix the two in a molar ratio of 1 : 1 and allow the solution of this to crystallize again, then
you get a salt Ca(OCl)Cl, a mixed chloride/hypochlorite. This material is a dry free flowing powder. In the past you could buy this as bleach chalk or
chlorine chalk. Nowadays, this hardly is made anymore and its use has been replaced by the use of Ca(ClO)2 or organic stuff like TCCA or Na-DCCA.
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