michalJenco - 9-5-2020 at 14:08
Hi fellow chemists.
I want to do some Finkelstein reactions in acetone but only have potassium iodide. Therefore I converted it by following the equation:
KI + NaOH --> NaI + KOH
I didn't realize, however, that my product would remain basic from KOH and I can't figure out how to wash the base away without .. you know ..
dissolving my product.
Does this make the route impossible or am I missing something? The base would obviously cause acetone to self-condense so I'm not even trying to work
with the base-contaminated stuff.
karlos³ - 9-5-2020 at 15:27
If you haven't done the stoichiometry correctly and still have KOH left... well, then neutralise it!
You can take advantage of the solubility of NaI in acetone I guess.
draculic acid69 - 9-5-2020 at 16:55
Neutralise to p.h.7 with vinegar evaporate to dryness and extract with acetone.im assuming potassium acetate is insoluble in acetone but I get the
feeling it is. I would avoid HCL as adding HCL to iodide salts changes colour and does weird things in my experience.
draculic acid69 - 9-5-2020 at 16:58
Just looked it up and yep it's insoluble
Fery - 9-5-2020 at 22:14
something similar discussed here:
https://www.sciencemadness.org/whisper/viewthread.php?tid=15...