Sciencemadness Discussion Board

Mn(3+)SO4

himler - 28-1-2019 at 13:41

does have anyone some knowledge about this, because im studdying this in
particulair and found that the is somuch bullshit on this , but Mn is not a criminal
or make people sick throug and believing lie’s

Ive done a experiment, ive dissolved some anisole and 2-propanone together
and added some lab grade Mn(OAc)2 to the solution. Than i added the oxidizer
KmnO4 and noticed that it dissolves into the 2-propanone , and the solution
turned violet. After some good stirring , ive heated slightley, maybe yet, put it
on the localheating of the building :-). After a while the dark brown solution turned
clear again. My question is: Does the elemental Mn3+ ion doing the actual oxidation
of 2-propanone or the acetic acid radical. With acetic acid one hydride transferr to
the Mn(III)Ac forming Mn(OAc)2 and one AcOH component. I respect any help
here ! And sorry for this bad language i type.

woelen - 29-1-2019 at 00:41

Your description is not very clear. Provide a stepwise description of what you have done and what were the results after each step.
E.g. it is not clear whether you dissolved the anisole, together with acetone, in water, or dissolved the anisole in acetone. In the title of the thread I see sulfate, where does this appear in your procedure?

oberkarteufel - 30-1-2019 at 00:51

I see some cookery here. Also, "elemental Mn3+ ion", LOL.

Mn3+ acetate can generate radicals out of acetone, which then react with the anisole. The resulting ketone is a drug precursor, that only requires adding NH2 group.

clearly_not_atara - 31-1-2019 at 00:47

Fortunately the ortho-methoxyamphetamine you would make from that isn't an active recreational drug. Presumably that means I can talk about it.

Mn(OAc)3 is infamously difficult to prepare. OP's method sounds like a very crude attempt at making it. I would be surprised if he isolated any 2'-methoxyphenyl-2-propanone.

oberkarteufel - 31-1-2019 at 03:07

I think that OP just rewrote some cookery recipe as something he did on his own.

Wouldn't be para- isomer preferred sterically?