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At the expense of a piece of glassware (attacked), I learned that a slurry of Ag2O will react with NaCl (or KCl) forming a white precipitate of AgCl
and aqueous NaOH (or correspondingly, KOH). Likely reactions:
Ag2O + H2O = 2 AgOH
AgOH + KCl = AgCl(s) + KOH
Treating cold dilute KOH with Cl2 forms KCl and KClO, as noted above.
If one adds Ag2O/AgOH, to NaClO, the reported product is AgCl precipitate and AgClO3. In other words, the silver hypochlorite disproportionates to the
insoluble chloride and chlorate.
[Edited on 8-8-2017 by AJKOER] |