Originally posted by WizardX
Quote: | Originally posted by almaslang
I will be trying those reactions and do a cost estimate.
I just need a Na free Pb2+, and a nearly pure NaOH |
Either this reaction 3 PbO + 2 NH3 ==> N2 + 3 H2O + 3 Pb when you precipitate PbO
OR
Electrolysis of plumbite ion is Pb(OH)3− |