| Search |
| [Next Page] |
Clarification: Differences between Moderators and Members
Moderators drink a bit less when logged in.
Moderators think straighter.
Moderators take a few ... |
25-3-2016 at 13:24
by: aga |
New Energetic Materials - Current Research
Lolololol
My teacher made and detonated a small atomic bomb in her jacket pocket yesterday.
No ... |
25-3-2016 at 12:38
by: aga |
Looking over the border: EU-Regulations
[rquote=443174&tid=23212&author=Mabus]So, it has come to this... banning shit.
EU is just w ... |
25-3-2016 at 12:25
by: aga |
Clarification: Differences between Moderators and Administrators
zts would probably have to do the research to give you the answer, so you may as well do it yourself ... |
25-3-2016 at 12:13
by: aga |
Stupid question - drying organics in an oven.
[rquote=443082&tid=65704&author=DraconicAcid]I'm really tired of having to clean crystals of ... |
24-3-2016 at 14:11
by: aga |
I called a few light material physicists, and they said MAYBE it could be possible to make a solid opaque element translucent wi
[rquote=443076&tid=65698&author=gatosgr]This is the first time I've heard light material phy ... |
24-3-2016 at 13:58
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
ok.
$$f'=2x\sqrt[3]{x^3-1}+\frac{x^2}{3}\frac{1}{(x^3-1)^{\frac23}}$$
$$f'=2x\sqrt[3]{x^3-1}+\frac ... |
24-3-2016 at 13:47
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
$$f=x^2\sqrt [3] {x^3-1}$$
$$f=x^2(x^3-1)^\frac13$$
Power rule & Product rule
$$f'=(x^2)'(x^3 ... |
24-3-2016 at 13:12
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
OK. z' and f' :
$$z=[\ln(x-2)]^3$$
power and chain rules ?
$$z'=3[ln(x-2)']^2$$
$$z'=3\Big(\frac ... |
24-3-2016 at 12:54
by: aga |
I called a few light material physicists, and they said MAYBE it could be possible to make a solid opaque element translucent wi
[rquote=443025&tid=65698&author=chemrox]Jon was doing this for awhile and I found out he'd b ... |
24-3-2016 at 09:50
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
1 and 1.
Bed time. Oooh ! That sounds pervy !
The derivative of that statement is that i'm off ... |
23-3-2016 at 16:12
by: aga |
Missing persons
vulture is still a mod too.
I guess this is basically j_sum1's wishlist, or an assumed list of ab ... |
23-3-2016 at 16:07
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
Bugger. 2 more to do, and they look harder.
Late here so tomorrow sirrah'
N.B. not the first d ... |
23-3-2016 at 15:54
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
Tantalatiousness !
I imagined a Spiral, where the change from one bit at the outside didn't chang ... |
23-3-2016 at 15:43
by: aga |
Missing persons
Personalities move on, get busy with other things, die etc.
Some re-incarnate with new usernames ... |
23-3-2016 at 15:07
by: aga |
Through the looking glass.
[rquote=442991&tid=65697&author=M0rphivm]I know quite a bit about chemistry[/rquote]
Yes, y ... |
23-3-2016 at 14:51
by: aga |
I called a few light material physicists, and they said MAYBE it could be possible to make a solid opaque element translucent wi
I called everyone on the planet and they all said you never called them, not even your mom.
Detri ... |
23-3-2016 at 14:40
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
Christ ! so the tiniest cock-up leads to enormously different results.
woelen is right : 100% met ... |
23-3-2016 at 14:14
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
$$v=(x^2+x+1)e^x+\frac{1}{x-1}$$
erm, er ... addition rule
$$v=[(x^2+x+1)e^x]+[\frac{1}{x-1}]$$
p ... |
23-3-2016 at 14:07
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
$$u=x^3e^{2-x}$$
Product rule ?
$$u=(x^3)(e^{2-x})$$
$$u'=(x^3)'(e^{2-x})+(x^3)(e^{2-x})'$$
... ... |
23-3-2016 at 12:16
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
[rquote=442902&tid=65532&author=j_sum1]Nope. The 2 is just a constant.
It probably looks ... |
23-3-2016 at 09:54
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
$$y=\frac{4\cos x}{\sin 2x}+3x$$
It looks like the sum rule and the quotient rule apply, so i'll ve ... |
23-3-2016 at 09:11
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
Not too bad for a beginner i guess.
This shakes the foundations a bit :
$$(2-x^3)'=-3x^2$$
Do ... |
23-3-2016 at 00:13
by: aga |
Calculus! For beginners, with a ‘no theorems’ approach!
I forgot that all the Masters of the B&D Uni go on the traditional bar and brothel crawl during ... |
22-3-2016 at 16:02
by: aga |
Salt Remover
Probably vinegar or phosphoric acid. |
22-3-2016 at 13:25
by: aga |
| [Next Page] |
